A、python
B、pdf
C、py
D、pyc
答案：C
解析：答案解析:
A、python
B、pdf
C、py
D、pyc
答案：C
解析：答案解析:
对以上数据,以性别字段作为分组依据,并对分组后的数据重新排序的语法正确的是()
A. frame[['ID']].groupby(frame('gender')).count().sortⱣⱤvalues(by=('gender'))
B. frame[['ID']].groupby(['gender']).count().sortⱣⱤvalues(by=frame['gender'])
C. frame[['ID']].groupby(('gender')).count().sortⱣⱤvalues(by=frame('gender'))
D. frame[['ID']].groupby(frame['gender']).count().sortⱣⱤvalues(by=['gender'])
解析：答案解析:
A. 对
B. 错
A. scatter()
B. plot()
C. bar()
D. pie()
A. pass
B. continue
C. break
D. try
A. length
B. index
C. count
D. find
A. 对
B. 错
A. print(s[3:5]) # 输出 lo
B. print(s[5:3]) # 输出空字符串
C. print(s[::-1]) # 输出!dlrow olleH
D. print(s[-1::-1]) # 输出!dlrow olleH
A. 删除字符串头尾指定的字符
B. 删除字符串末尾指定的字符
C. 删除字符串头部指定的字符
D. 通过指定分隔符对字符串切片
A. Letter[-1:-4:-1]
B. Letter( :3:2)
C. Letter[1:3:0]
D. Letter[ 'a': 'd': 2]
A. n=int(input())result=0foriinrange(n):ifi%2==1:result=result+iprint(result)
B. n = int(input())result = 0for i in range(1, n):if i % 2 == 1:result = result + iprint(result)
C. n = int(input())result = 0for i in range(n):result = result + iprint(result)
D. n = int(input())print(sum([i for i in range(n) if i % 2 == 1]))
